(3√7+5)(6√7-4)=
3/7-√5=
12√3/√6-√2![]()
3/7-√5=
12√3/√6-√2
Jawab:
[tex](3\sqrt{7} +5)(6\sqrt{7} -4)[/tex]
[tex]=(3\sqrt{7} )(6\sqrt{7} )+5(6\sqrt{7} )-((3\sqrt{7} )(4)-(5)(4)[/tex]
[tex]=126+30\sqrt{7} -12\sqrt{7}-20[/tex]
[tex]=106+18\sqrt{7}[/tex]
[tex]\frac{3}{7 -\sqrt{5} }[/tex]
[tex]=\frac{3}{7 -\sqrt{5} } \times\frac{7 +\sqrt{5} }{7 +\sqrt{5}}[/tex]
[tex]=\frac{3(7 +\sqrt{5})}{49-5}[/tex]
[tex]=\frac{3}{44} (7+\sqrt{5} )[/tex]
[tex]\frac{12\sqrt{3} }{\sqrt{6} -\sqrt{2} }[/tex]
[tex]=\frac{12\sqrt{3} }{\sqrt{6} -\sqrt{2} } \times\frac{\sqrt{6}+\sqrt{2}}{\sqrt{6}+\sqrt{2}}[/tex]
[tex]=\frac{12\sqrt{3}(\sqrt{6}+\sqrt{2}) }{6-2 }[/tex]
[tex]=\frac{12}{4} (\sqrt{18} +\sqrt{6} )[/tex]
[tex]=3(\sqrt{18} +\sqrt{6} )[/tex]
[answer.2.content]
